Tom K. answered 03/20/21
Knowledgeable and Friendly Math and Statistics Tutor
There is an exact answer and two approximations. Given that the expected value is "large enough" but not too large, I would expect the approximations to be fairly close.
I use Excel for all calculations; any software should match
Given that the problem mentions the expected number, my guess is that it expected the Poisson approximation to be used.
poisson.dist(76,82,1) = .2757
However, 82 is a bad approximation, as np = 360141*.000225 = 81.03173
Using this value, we get poisson.dist(76,81.03173,1) = .3122
This number becomes relevant as we show the other two results.
Exact uses the binomial distribution.
P(X <= 76) = binom.dist(76,360141,.000225,1) = .3122
This matches the Poisson with the correct expected value.
For the normal approximation, for P(X <= 76, we can use the continuity approximation, P(X <= 76.5)
norm.dist(76.5,360141*.000225,sqrt(360141*.000225*(1-.000225)),1) = .3073. This is close, but not as close as the other two. Note that, without the continuity correction, we would be further off.