
Jon S. answered 03/19/21
Patient and Knowledgeable Math and English Tutor
95% confidence interval of 0.2247 to 0.5753.
a. Find the point estimator for the interval
(0.2247 + 0.5753)/2 = 0.4
b. Find the margin of error
(0.5753 - 0.2247)/2 = 0.1753
c. Interpret the confidence level
95% confidence level means that there is a 95% probability the true population proportion is between 0.2247 and 0.5753.
d. Calculate the sample size used to create the interval
margin of error = z-critical * sqrt(p * (1-p)/n)
0.1753 = 1.96 * sqrt(0.4 * 0.6/n)
0.0894 = sqrt(0.24/n)
0.008 = 0.24/n
n = 0.24/0.008
n = 30