Find the measure of the largest angle in a triangle with sides having lengths 3√6, 6√3, and 9√2

Answer 1

It's a right triangle. Largest angle is 90 degrees

Largest angle is the angle opposite the longest side = 9sqr2 = the hypotenuse

the angle opposite the hypotenuse = 90 degrees or pi/2 radians

(9sqr2)^2 = 162

(3sqr6)^2 = 54

(6sqr3)^2 = 108

162 = 108+54 = 162

square of the hypotenuse = sum of squares of the other 2 sides