BC/DE= AC/EA
EC/DE=AC/AE
(28-AE)/5=28/AE
The solution to this quadratic wil give you a value for AE
CE=28-AE
BE=CE
Alyssa Z.
asked 03/18/21△ADE ~ △ABC.
Given:DE = 5, AC = 28, EC = BC
Find:BC |
(Enter your answers as a comma-separated list.) |
BC/DE= AC/EA
EC/DE=AC/AE
(28-AE)/5=28/AE
The solution to this quadratic wil give you a value for AE
CE=28-AE
BE=CE
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