CaCO3 + 2 HCl --> CaCl2 + CO2 + H2O. Starting with 20. grams CaCO3 and excess HCl, if only 2.7 g of H2O was produced, what is the % yield of this reaction?

Question

Limestone (CaCO3) dissolves in hydrochloric acid as shown by the equation: CaCO3 + 2 HCl --> CaCl2 + CO2 + H2O. Starting with 20. grams CaCO3 and excess HCl, if only 2.7 g of H2O was produced,

what is the % yield of this reaction?

Answer 1

CaCO3 + 2 HCl --> CaCl2 + CO2 + H2O ... balanced equation

Theoretical yield:

20.g CaCO3 x 1 mol CaCO3/100g x 1 mol H2O/mol CaCO3 x 18 g H2O/mol = 3.6 g H2O theoretical yield

Percent yield = actual yield / theoretical yield (x100%) = 2.7 g / 3.6 g (x100%) = 75.% yield