Calorimeter question

Question

A mixture of ammonia, NH3(g), and methane, CH4(g), is burned in an excess of oxygen in a bomb calorimeter. The heat released during this combustion reaction is 1377.65 kJ. If the calorimeter has a heat capacity of

15.6 kJ/°C, by how much will the calorimeter and its contents change in temperature? (Please show all the steps when solving this).

Answer 1

Heat released by the reaction = heat gained by calorimeter.

q = C_cal∆T

q = heat = 1377.65 kJ

C_cal = heat capacity of calorimeter = 15.6 kJ/º

∆T = change in temperature = ?

Solve for ∆T:

∆T = q / Ccal = 1377.65 / 15.6 kJ/º

∆T = 88.3º