Ho: mu = 150
Ha: mu < 150
alpha = 0.02 and Degrees of freedom = n - 1 = 17
from t-table critical value is -2.224
standard error = 11/sqrt(18) = 2.59
test statistic is t = (138-150)/2.59 = -4.63
since test statistic < critical value, reject Ho
There is evidence to conclude the treatment has a significance effect at alpha = 0.02.
Christina P.
Hello, I have a question how did you get a critical value of -2.224 can you please explain it will be greatly appreciated.03/17/21