chemistry hw help

Question

Calculate the mass of solvent in kg of a solution containing 5.22 mol of solute having Kb 2.42 C/m and that its boiling point changed by 1.22 C when a solute was added.

Answer 1

∆T = imK (assume i = 1 since the problem doesn't state what the solute is)

1.22º = (1)(m)(2.42º/m)

m = 1.22º / 2.42º/m)

m = 0.50413 mol/kg

5.22 mol / x kg = 0.50413 mol / 1 kg

x = 10.35 kg = 10.4 kg (3 sig. figs.)