chemistry hw help

Question

Calculate the molality of solution containing 4.63 mol of glucose dissolved in 650g of solvent. Then calculate the molal boiling point elevation constant if the boiling point elevated by 2.43 C.

Answer 1

∆T = imK

∆T = change in temperature = 2.43º

i = van't Hoff factor = 1 for glucose b/c glucose is a non electrolyte

m = molality = moles glucse/kg solvent = 4.63 mol/0.650 kg = 7.12 m

K = molal boiling point constant = ?

Solving for K...

K = ∆T / (i)(m)

K = 2.43º / (1)(7.12 m)

K = 0.341 º/m