MATH QUESTION 2

Question

A town's population has been growing linearly. In 2003 the population was 64,000. The population has been growing by 1200 people each year.

Write an equation for the population, P x years after 2003.

Find population in 2009.

Answer 1

Here the basic equation could be considered: P= 1200(x)+64000

2009-2003= 6 years (this is our X value)

knowing this we plug this into our original equation of P=1200(x)+64000

we get a final answer of 71,200 people

Answer 2

P = 64,000 + X1200

where,

P = Ending population

X = # of years

X = 2009-2003 = 6

substitute,

64000 + (6)1200 = 71,200