Compute z
z = (141.1 - 80.1)/10.5 = 5.8
141.1 would be 5.8 standard deviations above the mean - that would be very unusual.
Minimum usual value would be 2 standard deviations below the mean or 80.1 - 2*10.5 = 59.1
Jerry N.
asked 03/15/21A certain group of test subjects had pulse rates with a mean of 80.1 beats per minute and a standard deviation of 10.5 beats per minute. Would it be unusual for one of the test subjects to have a pulse rate of 141.1 beats perminute?
Minimum "usual" value= ________ beats per minute
(Type an integer or a decimal.)
Compute z
z = (141.1 - 80.1)/10.5 = 5.8
141.1 would be 5.8 standard deviations above the mean - that would be very unusual.
Minimum usual value would be 2 standard deviations below the mean or 80.1 - 2*10.5 = 59.1
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