what is the 8th term in a sequence whose first term is 4 and common ratio is ⅛

Answer 1

The fact that there is a common ratio tells us that this series is a geometric one, which has the general form:

a_n = a₁·r^n-1

where:

1. a_n = the nth term in the sequence
2. a₁ = the first term in the sequence = 4
3. r = the common ratio = 1/8
4. n = the term number, n = 1,2,3,4, ...

a_n = a₁·r^n-1

a_n = 4·(1/8)^n-1

To find the 8th term, set n = 8 in the above equation and compute the answer. Use you calculator to help.

a₈ = 4·(1/8)^8-1 = _____?