What is the solubility of Mg(OH)₂ at a pH of 12.10? (Ksp Mg(OH)₂ is 1.6 × 10⁻¹³)

Answer 1

Mg(OH)₂(s) <==> Mg²⁺(aq) + 2OH^-(aq)

Ksp = [Mg²⁺][OH^-]²

Let x = [Mg²⁺], then 2x = [OH^-]

Ksp = (x)(2x)²

1.6x10^-13 = 4x³

x³ = 4x10^-14

x = 3.4x10^-5 M = molar solubility of Mg(OH)₂