
Yefim S. answered 03/12/21
Math Tutor with Experience
This series converges conditionally: Series itself converges by alternative series test, but IanI = n2/(n3 + 1).
This series diverges by limit comparison test: lim [n2/(n3 + 1)]/(1/n) = 1 and because series bn = 1/n
n → ∞
diverges so series an = n2/(n3 + 1) diverges. Because given series conditionally convergent