If you start off with 130.0g of NaN3, how many grams of N2 would you make

Answer 1

What's the reaction? Could it be 2NaN₃ ==> 2Na + 3N₂ ??

molar mass of NaN₃ = 65.01 g/mol

moles NaN₃ present = 130.0 g x 1 mol/65.01 g = 1.9997 moles

For every 2 mol of NaN₃, you produce 3 moles of N₂ (see the balanced equation)

moles N₂ formed = 1.9997 mol NaN₃ x 3 mol N₂ / 2 mol NaN₃ = 2.9995 moles N₂

Grams of N₂ formed = 2.9995 moles N₂ x 28.00 g/mol N₂ = 83.99 g of N₂