Jake F.
asked 03/12/21Find cot θ if sec θ = square root of 7/2 and sin θ > 0
what is cot theta? help pls
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1 Expert Answer
Jon S. answered 03/12/21
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If sec = sqrt(7/2)
cos = 1 /sqrt(7/2)
cos^2 + sin^2 = 1
cos^2 = 1/ (7/2) = 2/7
2/7 + sin^2 = 1
sin^2 = 5/7
sin = sqrt(5/7)
cot = cos/sin = 1/sqrt(7/2) * sqrt(5/7) = 1/sqrt(5/2)
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Lester V.
so If sec = sqrt(7)/2 Then Cos = 1/sqrt(7)/2 That simplifies to (2*sqrt(7))/7 cos^2= 4/7 4/7 + sin^2=1 sin^2=3/7 sin = sqrt(21)/7 Cotagent = Cos/Sin ((2sqrt7)/7)/((sqrt21)/7 = (2√3)/303/03/22