Calculate ΔG° at 45°C for reactions for which

Question

(a) ΔH° = 293 kJ; Delta S° = -695 J/K

(b) ΔH° = -1137 kJ; Delta S°=0.496 kJ/K

(c) ΔH° = -86.6 kJ; Delta S° = -382 J/K

Answer 1

∆Gº = ∆Hº - T∆S

(a) ∆Gº = 293 kJ - (318K)(-0.695 kJ/K) = 293 kJ + 221 kJ

∆Gº = +514 kJ

Do the others the same way. Remember to change 45ºC to K and to change ∆Sº to kJ/K