one side of a square has endpoints (4,7) and (-3,5).what is the perimeter of the square?

Answer 1

calculate the distance between the 2 points, then multiply by 4 to get the perimeter

d^2 = 2^2 + 7^2 = 4+ 49 = 53 distance squared = sum of the squares of the differences in y values squared plus difference in corresponding x values squared. 7-5 = 2 4--3 = 7 2^2 =4 7^2 = 49

d = sqr53 = about 7.28

Perimeter = 4sqr53 = about 29.12