J.R. S. answered 03/11/21
Ph.D. University Professor with 10+ years Tutoring Experience
At STP, 1 mole of an ideal gas occupies 22.4 L.
Find moles of propane needed:
18.3 L x 1 mol/22.4 L = 0.817 moles propane needed
Mass of propane needed = 0.817 moles x 44 g/mol = 35.9 g propane