Because m<A = m<B, ABCD is an isosceles trapezoid.
The lower and upper base angles of an isosceles trapezoid are supplementary, so m<DCB = 180 - 54 = 126.
Since CF bisects <DCB, m<FCE = half m<DCB = 63.
Alyssa Z.
asked • 03/10/21Find:m∠FCE in degrees
Consider the following figure.
.
| Given:AB ∥ DC, m∠A = m∠B = 54°, |
CE ∥ DA, and CF bisects ∠DCB
|
Find:m∠FCE in degrees
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