Inactive Tutor answered 03/10/21
x=-3+3i
x+3 = 3i
(x+3)^2 =-9
x^2 +6x +9 =-9
x^2 +6x + 18 =0
(x-2)^2 =0
(x-4x+4) =0
(x^2-4x+4)(x^2+6x+18) = 0
x^4 + 2x^3 -20x +72 is the 4th degree polynomial with the given zeroes
Kalie W.
asked 03/10/21Form a polynomial f(x) with real coefficients having the given degree and zeros.
Degree:4
Zeros: -3+3i , 2 multiplicity 2
Anewer is in form: f(x) =a( )
Inactive Tutor answered 03/10/21
x=-3+3i
x+3 = 3i
(x+3)^2 =-9
x^2 +6x +9 =-9
x^2 +6x + 18 =0
(x-2)^2 =0
(x-4x+4) =0
(x^2-4x+4)(x^2+6x+18) = 0
x^4 + 2x^3 -20x +72 is the 4th degree polynomial with the given zeroes
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Kalie W.
It is x^4+2x^3-2x^2-48x+7203/11/21