What is the pressure of 1.12 moles of gas at 282K in a 23.2L container?

Answer 1

Hello, Loverlis,

As nyou noted, this is a gas law problem.

PV=nRT, where P is pressure, n is moles, R is the gas constant, and T is temperature in Kelvin.

Rearrange to sove for P:

PV=nRT

P= nRT/V

Make a table and enter the values:

P = (1.12 moles)*(0.0821 L*atm/mole*K)(282K)/23.2 L

P = 1.117 atm, or 1.12 atm to 3 sig figs

Bob