Finding Kp Value

Question

An equilibrium is established for the reaction 2 CO(g) + MoO₂(s) ⇌ 2 CO₂(g) + Mo(s). Use the expression for Kp from part a. If at equilibrium the partial pressure of carbon monoxide is 5.21 atm and the partial pressure of the carbon dioxide is 0.659 atm, then what is the value of Kp?

Answer 1

2 CO(g) + MoO₂(s) ⇌ 2 CO₂(g) + Mo(s)

Kp = (CO₂)² / (CO)² where ( ) is pressure . Note that solids are NOT included

Kp = (0.659)² / (5.21)²

Kp = 0.0160