Temperature of Reaction

Question

Determine the temperature of a reaction if K = 1.20 x 10⁻⁶ when ∆G° = +17.70 kJ/mol.

Answer 1

∆Gº = -RT ln K

∆Gº = 17.70 kJ/mol

K = 1.20x10^-6

R = gas constant = 8.314 J/Kmol = 0.008314 kJ/Kmol

T = temperature in K = ?

17.70 kJ/mol = -(0.008314) (T )(-13.63)

T = 156.2K