Finding Equilibrium Constant

Question

For the reaction: 2 A (g) + B (s) ⇌ 2 C (s) + D (g) At 298 K in a 10.0 L vessel, the equilibrium values are as follows: 0.721 atm of A, 4.18 mol of B, 6.25 mol of C, and 6.01 atm of D. What is the value of the equilibrium constant?

Answer 1

2 A (g) + B (s) ⇌ 2 C (s) + D (g)

0.721...............................6.01.........

Kp = (D) / (A)² note that solids are not included the equilibrium expression

Kp = 6.01 / (0.721)²

Kp = 11.6