a bus was going 30km/hr. six seconds later, it was going 24 km/hr. What was its acceleration?

Question

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Answer 1

We will use the formula

 

a = v/t

 

where:

a = acceleration

v = velocity

t = time

 

First, lets convert hours to seconds.

 

1 hr = 3600 s

 

v₁ = 30 km / hr = 30 km / 3600 s = 0.0083 km /s

v₂ = 24 km / hr = 24 km / 3600 s = 0.0067 km /s

t = 6 s

 

a = (v₂ - v₁) / t

a = (0.0067 km/s - 0.0083 km/s) / (6 s)

a = -0.00026 km /s²

 

The negative sign indicates acceleration in the direction opposite to the bus' direction of motion.  This means that the bus is slowing down.