Find all solutions of the equation in the interval [0,2pi). 4sinx = -cos²(x)+1. Write your answer in radians in terms of pi

Answer 1

0 radians

sin^2x -4sinx = 0

sinx(sinx-4) = 0.

xinx = 0

x = 0

ignore sinx-4=0 as sinx is always less than +1 and can never = 4