Al ​+​FeO​à​Fe ​+​Al2O3​Given .30 mol Al

Answer 1

2Al + 3FeO ==> 3Fe + Al₂O₃ ... Balanced equation

Now, what's the question?

moles Fe formed? 0.30 mol Al x 3 mol Fe / 2 mol Al = 0.45 mol Fe

moles Al₂O₃ formed? 0.30 mol Al x 1 mol Al₂O₃ /2 mo Al = 0.15 mol Al₂O₃

moles FeO used up? 0.30 mol Al x 3 mol FeO / 2 mol Al = 0.45 mol FeO