Find the exact valur of each of the remaining trigonometric functions of theta

Question

Cos theta= -8/9, pi/2<theta<pi

Answer 1

secx = -9/8 the inverse of cosx. 90<x<180 It's quadrant II

cosx =-8/9 = adjacent side/hypotenuse. opposite side = -sqr(81-64) = sqr17

sinx= sqr17/9

cscx= 1/sinx = 9/sqr17

tanx = sinx/cosx = sqr17/9 over -8/9 = -sqr17/8

cotx = 1/tanx = -8/sqr17

Answer 2

Cos theta= -8/9, pi/2<theta<pi

" " = -.888......

θ=152.733......°