J.R. S. answered 03/08/21
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Henderson Hasselbalch equation:
pOH = pKb + log [conj.acid]/[base]
pOH = 4.75 + log [0.15]/[0.25]
pOH = 4.75 + (-0.22)
pOH = 4.53
pH = 14 - 4.53
pH = 9.47