J.R. S. answered 03/05/21
Ph.D. University Professor with 10+ years Tutoring Experience
Start by writing the correctly balanced equation:
C5H12 + 8O2 ==> 5CO2 + 6H2O ... balanced equation
Next, find the limiting reagent:
80 g C5H12 x 1 mol C5H12 / 72 g x 5 mol CO2 / mol C5H12 x 44 g CO2/mol CO2 = 244 g CO2
240.0 g O2 x 1 mol O2 / 32 g x 5 mol CO2 / 8 mol O2 x 44 g CO2 / mol CO2 = 206 g CO2