John M. answered 03/05/21
Certified Math Teacher with Statistics Masters
There are two approaches to this problem. The easiest one would be to graph the circle and see which point is outside the circle.
The second approach would be to plug the x and y values into the equation to see how the left side compares to the right side. If (x + 6)2 + (y - 2)2 < 25, the point is interior. If (x + 6)2 + (y - 2)2 > 25, the point is exterior.
For (-7, 3), (-7 + 6)2 + (3 - 2)2 = 2 < 25 so it is interior.
For (-3, 1), (-3 + 6)2 + (1 - 2)2 = 10 < 25 so it is interior.
For (0, 0), (0 + 6)2 + (0 - 2)2 = 40 > 25 so it is exterior.
For (-3, 5), (-3 + 6)2 + (5 - 2)2 = 18 < 25 so it is interior.
Point (0, 0) is not an interior point.
Luisa R.
Thank u so much !03/05/21