Sorry for asking for more help :(

Question

How many liters of 3.87 M sulfuric acid are required to fully neutralize 698.5 mL of 8.16 M lithium hydroxide?

Sorry I keep asking for help, but no matter how I do the problems or work them out I don't get the right answer and because I always do something wrong my grade is suffering severely.

Answer 1

Lithium hydroxide and Sulfuric acid react with each other in a 2:1 ratio

Moles of Lithium hydroxide is calculated by multiplying the molarity of Lithium hydroxide with its volume in liters = 0.6985 liters * 8.16 = 5.70 moles

The moles of Sulfuric acid must be 5.70/2 = 2.85 moles

The molarity of sulfuric acid is 3.87 and the moles are 2.85

Using the equation Molarity = Moles/liters we can calculate the liters to be 0.74 liters

Liters = moles/Molarity