J.R. S. answered 03/03/21
Ph.D. University Professor with 10+ years Tutoring Experience
Stoichiometry simply relates the moles of each compound in the balanced equation. So in the current problem, the stoichiometry tells us that all of the compounds are in a 1 : 1 mol ratio. So, 1 mol CuSO4 reacts with 1 mol Ag2CO3 to produce 1 mol Ag2SO4 and 1 mol of CuCO3.
We are given GRAMS (not moles) of CuSO4, so we must convert this to moles (stoichiometry is in moles not grams). 42 g CuSO4 x 1 mol CuSO4 / 160 g = 0.2625 moles CuSO4
Now we can relate (on a mole basis) CuSO4 to CuCO3 since they are in a 1 : 1 mol ratio.
Moles of CuCO3 produced: 0.2625 mol CuSO4 x 1 mol CuCO3 / 1 mol CuSO4 = 0.2625 mol CuCO3
Rounding to 2 sig. figs. we have 0.26 moles CuCO3