Chemistry II Boiling Point of Aqueous Solution

Question

MgCl₂ has a van't Hoff factor of 2.70. What would be the boiling point (in °C) of an aqueous solution containing 1.90 mol of MgCl₂ in 1.00 kg of water? (Kb for water is 0.512 °C/m. The boiling point for water is 100.0˚C.)

Answer 1

Just as in the other questions I've answered for you

∆T = imK

Solving for ∆T

∆T = (2.70)(1.90 mol/1.0 kg)(0.512) = 2.63º

Boiling point of solution = 100.0 + 2.63 = 102.6ºC