
Brandon B. answered 03/02/21
Physics PhD. 10+ years teaching calculus based physics.
Arc length is ∫ds = ∫(dx2+dy2)1/2 = ∫(1 + dy2/dx2)1/2 dx. So we see that dy/dx = cosx ⇒ y = sinx + C. y(0) = 0 ⇒ C = 0.
Cameron L.
asked 03/02/21Find the equation of the curve that passes through the point (x, y) = (0, 0) and has an arc length on the interval given by the integral
A | y = sin(x) |
B | y = cos(x) |
C | y = cos-1(x) |
D | y = tan(x) |
Brandon B. answered 03/02/21
Physics PhD. 10+ years teaching calculus based physics.
Arc length is ∫ds = ∫(dx2+dy2)1/2 = ∫(1 + dy2/dx2)1/2 dx. So we see that dy/dx = cosx ⇒ y = sinx + C. y(0) = 0 ⇒ C = 0.
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