Assuming BC and CA are legs of the right triangle, then the hypotenuse AB = 13 (By the Pythagorean Theorem).
Sin B = CA/AB = 12/13
Cos B = BC/AB = 5/13
Tan B = CA/BC = 12/5
Cot B = 1/Tan B = 5/12
Csc B = 1/Sin B = 13/12
Sec B = 1/Cos B = 13/5
Woojin L.
asked 03/02/21triangle ABC is a right triangle
CA=12
BC=5
Assuming BC and CA are legs of the right triangle, then the hypotenuse AB = 13 (By the Pythagorean Theorem).
Sin B = CA/AB = 12/13
Cos B = BC/AB = 5/13
Tan B = CA/BC = 12/5
Cot B = 1/Tan B = 5/12
Csc B = 1/Sin B = 13/12
Sec B = 1/Cos B = 13/5
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