
Yefim S. answered 03/01/21
Math Tutor with Experience
Slope m of tangent line m = dy/dx at θ = π/6.
x = rcosθ = (1 + cosθ)cosθ = cosθ + cos2θ;
y = rsinθ = (1 + cosθ)sinθ = sinθ + 0.5sin2θ.
dy/dx = (dy/dθ)/dx/dθ) = (cosθ + cos2θ)/(- sinθ - sin2θ);
Slope m = (cosπ/6 + cosπ/3)/(- sinπ/6 - sinπ/3) = (√3/2 + 1/2)/(- 1/2 - √3/2) = - 1.
Answer is A