A particle moves in the x-y plane for t > 0 so that x(t) = t3 - 4t and y(t) = et. At time t = 1, the particle is moving

Question

A particle moves in the x-y plane for t > 0 so that x(t) = t³ - 4t and y(t) = e^t. At time t = 1, the particle is moving

A	to the left and up
B	to the right and up
C	to the left and down
D	to the right and down

Answer 1

v_x(t) =x'(t) = 3t² - 4 and at t = 1 v_x(1) = 3 - 4 = - 1 < 0;

v_y(t) = y'(t) = e^t; v_y(1) = e > 0

So, at t = 1 particle moving to the left and up

Answer is A