J.R. S. answered 02/28/21
Ph.D. University Professor with 10+ years Tutoring Experience
Dalton's Law of Partial Pressures and Raoult's Law:
Vapor pressure of pure liquid A = 350 mm Hg
Vapor pressure of pure liquid B = 100 mm Hg
Total vapor pressure of solution = 450 mm Hg
XA = mol fraction A in the solution = 350 / 450 = 0.778
XB = mol fraction B in the solution 1 - 0.778 = 0.222
Vapor pressure of A in "steam" or in the vapor phase = 0.778 x 350 mm Hg = 272 mm Hg
Vapor pressure of B in "steam" or in the vapor phase = 0.222 x 100 mm Hg = 22.2 mm Hg
Total pressure in vapor phase = 294.2 mm Hg
XA in the vapor phase = 272 mm Hg / 294 mm Hg = 0.925
If this is 2x the mol fraction of A in the liquid, the mol fraction of A in the liquid would be 0.925/2 = 0.463