(18) Find an equation of the tangent line to the graph of y​ = f(x) at the given x. ​f(x)​ = (Square Root)x, x = 16/25

Question

What is the equation of the tangent​ line?

___________ (​Type your answer in​ point-slope form).

Answer 1

f'(x)=1/[2sqrt(x)]

at x = 16/25 f'(x)=5/8

at x=16/25, y = 4/5

equation of tangent: 5/8= (y-.8)/(x-.64)...and this is point-slope form