Hi Bon,
This is a classic distance (d) = rate (r) * time (t) problem. The question asks you what time Devin and Antonio will meet, so clearly, you need to solve for a time (t). Although there is not a ton of information, I suggest you write everything down. It is a good habit to develop for when you take more math courses in the future. So, what do you know?
Well, firstly, you know that the distance d = 192 mi. You also have two rates Antonio's rate (let's call it Ar) = 14 mph and Devin's rate (Dr) = 10 mph.
However, Devin and Antonio are going in opposite directions. If I had the option to draw, I would show you a line with a middle point showing where arrows pointing to each other meet. Anyway, you need to create a small system of equations using this meeting position, which we will call x.
So, the first equation is 192 - (Ar)*t = x and the second equation is (Dr)(t) = x. Because it is the same position, you can simply use the substitution method to create one easy equation in which you can solve for t. This equation becomes 192 -(Ar)t = (Dr)t. Now, let's plug the rates and distances we wrote down earlier and solve for t. So, you get 192 mph - (14 mph)*t =10 mph (t). Now, can you proceed and solve this single variable equation for t? If not, feel free to follow up with me.