Ian B. answered • 02/27/21
Recent Ivy League Graduate with Experience Tutoring Math
Wow! That internet cafe must be really good if it took Haley six hours to get there.
Anyway, another d=rt problem. This time they give us two different rates and two different times. So, first, let's write down what we know. The total distance D = 46 miles and the total time T = 6 hours. We also have two rates: rb (bike rate) = 11 mph and rw (walk rate) = 6 mph. We need two separate times to account for these different rates. tb for the time she rides her bicycle and tw for the time she walks after she gets a flat tire (that's really unfortunate). So, the tb and tw add up to the total time up 6 hours because she is only making a trip in one direction. T = tb + tw. After substituting what you know, you should then gett 6 -tw=tb. You can then return to your total distance equation and substitute total D as 46 mi and then you can split the distant and times into their respective mode of travel. So, you get 46 mi = rb(tb) + rw*(tw). You know both rates and tb = 6 - tw, so substitute all your knowns into this total equation and solve for tw.
I've noticed you have had asked about a lot with problems with distance equals rate times time problems. Do you feel like you have a strong grasp of this material? If not, I suggest you try to work out some more problems on your own. If that does not work out, it would be a good idea to reserve a lesson with an instructor on Wyzant. We can go more in-depth with you and address more specific questions that you might have. Best of luck with Algebra!
