What is the theoretical yield of MgCl2in moles? In grams?

Answer 1

Mg(s) + 2HCl(aq) ==> MgCl₂(aq) + H₂(g) ... balanced equation

Using dimensional analysis, we can find the theoretical yield of MgCl₂ (in moles):

6.00 g Mg x 1 mol Mg / 24.31 g x 1 mol MgCl₂ / mol Mg = 0.247 moles MgCl₂ (3 sig. figs.)