When iron(II) chloride reacts with silver nitrate, iron(II) nitrate and silver chloride are produced. The balanced equation for this reaction is:

Question

When iron(II) chloride reacts with silver nitrate, iron(II) nitrate and silver chloride are produced. The balanced equation for this reaction is:

FeCl2 (aq) + 2AgNO3 (aq) ----> Fe(NO3)2 (aq) + 2AgCl (s)

If 3 moles of iron(II) chloride react,

The reaction consumes= ..........moles of AgNO3

The reaction produces= ...........moles of Fe(NO3)2 and ............moles of AgCl

Answer 1

FeCl₂ (aq) + 2AgNO₃ (aq) ----> Fe(NO₃)₂ (aq) + 2AgCl (s)

From the balanced equation we use the mol ratio of iron(II) chloride (FeCl₂) to silver nitrate (AgNO₃). It is 1:2, i.e 1 mol FeCl₂ reacts with 2 mols AgNO₃.

3 moles FeCl₂ x 2 mol AgNO3/1 mol FeCl₂ = 6 moles AgNO₃ consumed

Similarly, the ratio between FeCl₂ and Fe(NO₃)₂ is 1 : 1, so ...

3 mol FeCl₂ produces 3 mol Fe(NO₃)₂

Mole ratio of FeCl₂ to AgCl = 1:2, so...

3 mol FeCl₂ x 2 mol AgCl / mol FeCl₂ = 6 mol AgCl produced