Chemistry problem

Question

Hello, I have a question about butane or also called C4H10 . I need to write how much oxygen dioxide (Co2) comes out from burning 5.8grams butane. Please help me . Thank you

Answer 1

The equation for this reaction is

2C₄H₁₀ + 13O₂ ==> 8CO₂ + 10H₂O

So, 2 moles butane generates 8 moles of CO₂ (4 times of 1: 4 ratio). So all we need to do is convert 5.8 g butane to moles and then multiply by 4 to get moles of CO₂. We then convert moles of CO₂ to g of CO₂

5.8 g C₄H₁₀ x 1 mol C₄H₁₀ / 58 g = 0.10 moles C₄H₁₀

0.10 moles C₄H₁₀x 8 moles CO₂ /2 moles C₄H₁₀ = 0.40 moles CO₂

0.40 moles CO₂ x 44 g CO₂ / mole CO₂ = 17.6 g CO₂ = 18 g CO₂