J.R. S. answered 02/25/21
Ph.D. University Professor with 10+ years Tutoring Experience
Buffers:
Use of Henderson Hasselbalch equation...
pOH = pKb + [ conj.acid]/[base]
pKb = -log 4.4x10-4 = 3.36
pOH = 3.36 + log (0.35/0.15) = 3.36 + 0.37
pOH = 3.73
pH = 14 - 3.73
pH = 10.27 = 10.3