J.R. S. answered 02/25/21
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Buffers:
Use of Henderson Hasselbalch equation...
pH = pKa + log [conj.base]/[acid]
pKa = -log 4.5x10-4 = 3.35
pH = 3.35 + log (0.35/0.15) = 3.35 + 0.368
pH = 3.72