J.R. S. answered 02/25/21
Ph.D. University Professor with 10+ years Tutoring Experience
a). BaCO3(s) <==> Ba2+(aq) + CO32-(aq)
b). molar mass BaCO3 = 197 g/mol
7.9x10-4 g x 1 mol / 197 g /0.1 L = 4.0x10-5 mol/L
c). Ksp = [Ba2+][CO32-] = (4.0x10-5)2
Ksp = 1.6x10-9