J.R. S. answered 02/25/21
Ph.D. University Professor with 10+ years Tutoring Experience
Ni(CO)₄(g) ⇌ Ni(s) + 4 CO(g)
0.105 M.........................0.302 M.........I
Qc = [CO]4 / [Ni(CO)4 (NOTE: no need to even include the 32.0 g Ni as it is a solid and does not participate in the equilibrium expression)
Qc = (0.302)4 / (0.105)
Qc = 0.0792

J.R. S.
03/11/21
MACEY W.
You may have your math wrong. Remember to do (0.105^4)/(0.302) not (0.105)(4)/(0.302) which is 0.0792 = Qc03/11/21